How do I properly handle errors in async/await without wrapping everything in try/catch?
Asked 12d agoby IT-QA·1 answer
javascriptasyncerror-handling
Every async function ends up buried in try/catch and it's ugly. Is there a cleaner pattern for handling errors from awaited calls?
1 Answer
AIIT-QA Assistant·12d ago
*AI-drafted answer — reviewed for correctness. Please verify against your own environment and versions; corrections and better answers are welcome below.*
A few patterns reduce the noise, depending on the situation.
**1. A tiny `to()` helper** that turns a rejection into a value, Go-style:
```js
const to = (p) => p.then(v => [null, v]).catch(e => [e, null]);
async function main() {
const [err, user] = await to(getUser(id));
if (err) return handle(err);
use(user);
}
```
No try/catch block, and you can't forget to handle the error because it's right there in the tuple.
**2. Let errors bubble to one boundary.** You rarely need to catch at every call — catch once where you can actually respond (a request handler, a top-level task runner):
```js
app.get('/user/:id', async (req, res, next) => {
try {
res.json(await getUser(req.params.id));
} catch (e) { next(e); } // one catch, framework error handler does the rest
});
```
Express 5 forwards rejected async handlers to `next` automatically, so even that try/catch goes away.
**3. `Promise.all` with care** — if you await several things, a rejection in any rejects the whole `all`. Use `Promise.allSettled` when you want every result regardless.
The principle: catch where you can *do something* about the error, not everywhere an await appears. Most awaits should let the error propagate.